Solution 1:
s := strings.Split("127.0.0.1:5432", ":")
ip, port := s[0], s[1]
fmt.Println(ip, port)
Solution 2:
host, port, err := net.SplitHostPort("127.0.0.1:5432")
fmt.Println(host, port, err)
Solution 3:
Since go is flexible an you can create your own python style split
package main
import (
"fmt"
"strings"
"errors"
)
type PyString string
func main() {
var py PyString
py = "127.0.0.1:5432"
ip, port , err := py.Split(":") // Python Style
fmt.Println(ip, port, err)
}
func (py PyString) Split(str string) ( string, string , error ) {
s := strings.Split(string(py), str)
if len(s) < 2 {
return "" , "", errors.New("Minimum match not found")
}
return s[0] , s[1] , nil
}
Reference:
http://stackoverflow.com/questions/16551354/how-to-split-a-string-and-assign-it-to-variables-in-golang
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