$.ajax({
type: 'POST',
url: "/",
data: {},
dataType: 'json',
xhr: function() {
$('#formLoadingDiv').show();
var xhr = new window.XMLHttpRequest();
xhr.upload.addEventListener("progress", function(evt) {
if (evt.lengthComputable) {
var percentComplete = evt.loaded / evt.total;
//Do something with upload progress here
}
}, false);
xhr.addEventListener("progress", function(evt) {
if (evt.lengthComputable) {
var percentComplete = evt.loaded / evt.total;
//Do something with download progress
}
}, false);
return xhr;
},
})
.done(function(data) {
if (data.status === true) {} else if ('errors' in data) {
console.log(data);
}
})
.fail(function() {
console.log('failed');
})
.always(function() {
$('#formLoadingDiv').hide();
});
Reference:
http://stackoverflow.com/questions/19126994/what-is-the-cleanest-way-to-get-the-progress-of-jquery-ajax-request
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